递归写法
visited = set()
def dfs(node, visited):
if node in visited: # terminator
# already visited
return
visited.add(node)
# process current node here.
...
for next_node in node.children():
if next_node not in visited:
dfs(next_node, visited)
非递归写法
def DFS(self, root):
if tree.root is None:
return []
visited, stack = [], [root]
while stack:
node = stack.pop()
visited.add(node)
process (node)
# 生成相关的节点
nodes = generate_related_nodes(node)
stack.push(nodes)
# other processing work
...
//C/C++
//递归写法：
map<int, int> visited;
void dfs(Node* root) {
// terminator
if (!root) return ;
if (visited.count(root->val)) {
// already visited
return ;
}
visited[root->val] = 1;
// process current node here.
// ...
for (int i = 0; i < root->children.size(); ++i) {
dfs(root->children[i]);
}
return ;
}
//非递归写法：
void dfs(Node* root) {
map<int, int> visited;
if(!root) return ;
stack<Node*> stackNode;
stackNode.push(root);
while (!stackNode.empty()) {
Node* node = stackNode.top();
stackNode.pop();
if (visited.count(node->val)) continue;
visited[node->val] = 1;
for (int i = node->children.size() - 1; i >= 0; --i) {
stackNode.push(node->children[i]);
}
}
return ;
}
Java
public List<List<Integer>> levelOrder(TreeNode root) {
List<List<Integer>> allResults = new ArrayList<>();
if(root==null){
return allResults;
}
travel(root,0,allResults);
return allResults;
}
private void travel(TreeNode root,int level,List<List<Integer>> results){
if(results.size()==level){
results.add(new ArrayList<>());
}
results.get(level).add(root.val);
if(root.left!=null){
travel(root.left,level+1,results);
}
if(root.right!=null){
travel(root.right,level+1,results);
}
}
const visited = new Set()
const dfs = node => {
if (visited.has(node)) return
visited.add(node)
dfs(node.left)
dfs(node.right)
}